V^2+22v+40=8v

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Solution for V^2+22v+40=8v equation:


Simplifying
V2 + 22v + 40 = 8v

Reorder the terms:
40 + V2 + 22v = 8v

Solving
40 + V2 + 22v = 8v

Solving for variable 'V'.

Move all terms containing V to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + V2 + -40 + 22v = -40 + 8v

Reorder the terms:
40 + -40 + V2 + 22v = -40 + 8v

Combine like terms: 40 + -40 = 0
0 + V2 + 22v = -40 + 8v
V2 + 22v = -40 + 8v

Add '-22v' to each side of the equation.
V2 + 22v + -22v = -40 + 8v + -22v

Combine like terms: 22v + -22v = 0
V2 + 0 = -40 + 8v + -22v
V2 = -40 + 8v + -22v

Combine like terms: 8v + -22v = -14v
V2 = -40 + -14v

Simplifying
V2 = -40 + -14v

Reorder the terms:
40 + V2 + 14v = -40 + -14v + 40 + 14v

Reorder the terms:
40 + V2 + 14v = -40 + 40 + -14v + 14v

Combine like terms: -40 + 40 = 0
40 + V2 + 14v = 0 + -14v + 14v
40 + V2 + 14v = -14v + 14v

Combine like terms: -14v + 14v = 0
40 + V2 + 14v = 0

The solution to this equation could not be determined.

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